Light – Reflection and Refraction

The image formed by a concave mirror is observed to be virtual, erect and larger than the object. Where should be the position of the object?
(a) Between the principal focus and the centre of curvature
(b) At the centre of curvature
(c) Beyond the centre of curvature
(d) Between the pole of the mirror and its principal focus.

(d) Between the pole of the mirror and its principal focus. The position of the object should be between the pole and principal focus.

A convex lens forms a real and inverted image of a needle at a distance of 50 cm from it. Where is the needle placed in front of the convex lens if the image is equal to the size of the object? Also, find the power of the lens.

The position of the image at 2F since the image is real and the same size. It is given that the image of the needle is formed at a distance of 50 cm from the convex lens. Therefore, the needle is placed in front of the lens at a distance of 50 cm. Object distance …

A convex lens forms a real and inverted image of a needle at a distance of 50 cm from it. Where is the needle placed in front of the convex lens if the image is equal to the size of the object? Also, find the power of the lens. Read More »

Find out, from the table, the medium having the highest optical density. Also, find the medium with the lowest optical density.

Lowest optical density = AirHighest optical density = Diamond A medium’s refractive index and optical density are inversely proportional. The optical density of a medium depends on its refractive index, and vice versa. The table shows that the refractive indices of diamond and air are, respectively, the lowest and highest. As a result, diamond has …

Find out, from the table, the medium having the highest optical density. Also, find the medium with the lowest optical density. Read More »