An object of 5 cm is placed at a distance of 20 cm in front of a convex mirror with a radius of curvature of 30 cm. Find the position, nature and size of the image.

Object distance (u) = – 20 cm

Image distance (v) = ?

Object height (h) = 5 cm

Image height (h’) =?

Radius of curvature (R) = 30 cm

Radius of curvature = 2 × Focal length

R = 2f

f = 15 cm

The positive value of image height indicates that the image formed is erect.

Hence, the image formed is erect, virtual, and smaller in size.

Ray diagram