Object distance (u) = – 20 cm Image distance (v) = ? Object height (h) = 5 cm Image height (h’) =? Radius of curvature (R) = 30 cm Radius of curvature = 2 × Focal length R = 2f f = 15 cm The positive value of image height indicates that the image formed …
A plane mirror’s positive sign indicates a virtual, erect image. Given that the magnification is 1, the image’s size equals to the object’s size.
Focal length of convex mirror (f) = +15 cm Object distance (u) = – 10 cm Image distance (v) =? According to the mirror formula, The image is virtual, erect and diminished. The image is located at a distance of 6 cm from the mirror on the other side of the mirror. The positive and …
focal length (f) = – 15 cm Distance of image (v) = – 10 cm The negative value of u indicates that the object is placed 30 cm in front of the lens. This is shown in the following ray diagram.
Height of the object,( h1 ) = 5 cm Height of the image,( h2 ) = ? Distance of the object from the converging lens,( u) = -25 cm Distance of the image from the converging lens,( v) =? Focal length of a converging lens,(f) = +10 cm Using the lens formula, Thus, the image …
Yes, as shown in the image, it will produce a complete image of the object. By watching the images of a far-off object, such as a tree, on a screen when the lower half of the lens is covered with black paper, this can be verified experimentally. However, the image’s clarity or brightness will decrease.
(a) Concave Mirror: When the light source is positioned at their main focus, concave mirrors can produce a powerful parallel beam of light. (b)Convex mirrors have the largest fields of view (b). (c) Concave mirror: Because it concentrates the sun’s parallel beams into a single point.
Range of the object’s distance from the mirror’s pole is 0 to 15 cm. The image is erect, virtual, and larger than the object.
(c) A convex lens of focal length 5 cm When reading tiny letters in a dictionary, a convex lens with a 5 cm focal length can be utilised.
