JSIERT

With the addition of oxygen (O2) in the first equation, the sodium (Na) becomes oxidised, and the reduction of copper (Cu) in the second equation results from the addition of hydrogen (H2).

Reaction A double displacement reaction can be seen between sodium chloride (NaCl) and silver nitrate (AgNO3). Due to the production of a white silver chloride precipitate, positive and negative ions exchange positions during the reaction. The chemical is explained below : Ag+ + NO3– + Na+ + Cl– → AgCl + Na+ + NO3–

Because iron is more reactive than copper, it displaces copper from the copper sulphate solution when an iron nail is dipped in the solution. As a result, the copper sulphate solution\’s colour changes from blue to green. The result is CuSO4 ( Blue) + Fe → FeSO4 (Green) + Cu

Because water gets hydrolyzed to produce H2 and O2 gas in activity 1.7, the amount of gas collected in one of the test tubes is double that of the other. Here, two molecules of hydrogen and one molecule of oxygen are released as a result of electrolysis; as a result, there will be twice as …

Why is the amount of gas collected in one of the test tubes in Activity 1.7 double the amount collected in the other? Name this gas. Read More »

(i) The substance ‘X’ which is used in whitewashing is quick lime or Calcium Oxide and its formula is CaO. (ii) CaO + H2O → Ca(OH)2

(i) BaCl2 + Na2SO4 → BaSO4 + 2NaCl (ii) NaOH + HCl → NaCl + H2O

i) H2 + Cl2 → 2HCl ii) 3BaCl2 + Al2(SO4)3 →3BaSO4 + 2AlCl3 iii) 2Na + 2H2O → 2NaOH + H2

Magnesium metal reacts with air oxygen to generate magnesium oxide (MgO), a very stable chemical, hence magnesium ribbon needs to be cleaned before burning in the air. Therefore, it is necessary to clean the ribbon by removing the layer of MgO in order to prevent further reactions with oxygen.